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NaOH Volume Needed to Neutralize HCl: Fact Check Result

“0.589 M NaOH neutralizing 52.1 mL of 0.821 M HCl: 72.6 mL”
Statement is correct
Confidence: High Checked on April 5, 2026

Summary

Neutralizing 52.1 mL of 0.821 M HCl requires 0.0428 mol of acid. At 0.589 M NaOH, that amount corresponds to 0.0726 L, or 72.6 mL, of base. Therefore the quoted volume is accurate.

Recheck this fact Runs a fresh check with up-to-date sources

Sources 60 searched

pubchem.ncbi.nlm.nih.gov
  • Sodium Hydroxide | NaOH | CID 14798 - PubChem - NIH

    Sodium Hydroxide | NaOH or HNaO | CID 14798 - structure, chemical names, physical and chemical properties, classification, patents, literature, biological activities, safety/hazards/toxicity information, supplier lists, and more.

wwwn.cdc.gov
sciencedirect.com
cerritos.edu
chem.fsu.edu
  • Stoichiometry

    This equation is all 1:1 relationships, 1 mole of NaCl is made for every 1 mole of HCl or NaOH etc.

eiu.edu
ck12.org
content.njctl.org
chem.libretexts.org

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