NaOH Volume Needed to Neutralize HCl: Fact Check Result
“0.589 M NaOH neutralizing 52.1 mL of 0.821 M HCl: 72.6 mL”
Summary
Neutralizing 52.1 mL of 0.821 M HCl requires 0.0428 mol of acid. At 0.589 M NaOH, that amount corresponds to 0.0726 L, or 72.6 mL, of base. Therefore the quoted volume is accurate.
Sources 60 searched
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