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Cis‑but‑2‑ene and trans‑but‑2‑ene react with bromine

Question asked:

“Both cis‑but‑2‑ene and trans‑but‑2‑ene can react with bromine because they contain a carbon‑carbon double bond.”
True
Confidence: High Checked on October 13, 2026

Summary

Both cis‑but‑2‑ene and trans‑but‑2‑ene possess a carbon‑carbon double bond, which makes them reactive toward bromine in an electrophilic addition reaction. The addition proceeds via a bromonium ion intermediate, yielding dibrominated products for each isomer.

Sources 60 searched

sciencedirect.com
  • 2-Methylbut-2-Ene - an overview | ScienceDirect Topics

    The Br• reacts with the alkene, and the resulting product is an alkyl radical intermediate that reacts with more HBr to yield the anti-Markovnikov product, and more bromine radical. If a reaction generates a carbocation, Markovnikov orientation is sure to result.

ladykeanecollege.edu.in
mysite.du.edu
  • Du

    A Br2 molecule (red and blue) is preparing to add to an molecule of cis-2-butene. The Br2 approaches from below (or above) the plane of the atoms of the double bond because this is the location of the electron density of the pi bond. As the red Br leaves, the blue Br becomes electrophilic and ...

chemvista.org
  • Stereochemistry of addition to cis and trans 2-Butene

    Bromine adds on to the cis isomer giving rise to (±)-2,3-Dibromobutane while the trans isomer leads to meso-Dibromobutane exclusively. These results are consistent with the two step mechanism with bromonium ion intermediate. The carbocation intermediate would have given rise to the meso-Dibromo ...

chem.libretexts.org
masterorganicchemistry.com
  • Bromination of alkenes with Br2 to give dibromides – Master Organic Chemistry

    Everywhere I’ve read, in an alkene reaction both Br’s attache to the ring in trans.. Could you show the mechanism involved? ... I believe only 1 Br attaches because it is a radical reaction, hence the “light”. Being radical means only 1 attaches during propagation ... Yeah I just looked this up because I was confused too. When you have light plus Br2 plus an alkene you get allylic bromination, which means a bromine radical removes a hydrogen (and one electron from its bond) from a carbon adjacent to the double bond (in allylic position), leaving only one electron on that carbon which reacts with another Br2 to take one of the bromines and one of its electrons to form a halogenated alkene and another bromine radical in the propagation step.

byjus.com
testbook.com

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